Question

Four equal circles, each of radius 5 cm, touch each other as shown in Fig. Find the area included between them (Take $\pi =3.14$)

Answer 1

It is given that four equal circle touches each other as shown in figure.

Let the side of square be= a.

then a= 5+5

=10 cms

We know that

Area of a circle = $\pi$ $r^2$

= $\frac{22}{7}$ x r x r

=3.14 x 5 x 5

= $78.5c{m}^2$

Area of a quadrant inside the square is given by $\frac{1}{4}$ $\pi$ $r^2$

= =14× $78.5c{m}^2$

Area of the shaded region = Area of the square- 4.( Area of the quadrant)

= 100 - ( 4) . $\frac{1}{4}$ .( 78.5)

= 100- 78.5

= $21.50c{m}^2$