Question

Four fair six-sided dice are rolled. The probability that the sum of the results being 22 is x/1296. The value of X is .

• A. 10

Answer 1

The correct option is A 10
Sample space
= {(1, 1, 1, 1), (1, 1, 1, 2), ....., (6, 6, 6, 6)
$=6^4=1296$
Favourable cases = {sum should be 22} = 4 + 6 = 10 ways
Because sum 22 can occur

So P(sum is 22)
$=\frac{X}{1296}=\frac{10}{1296}$
$\Rightarrow X=10$