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Question

Four geometric means are inserted between 18 and 128. Find the third geometric mean?

A
4
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B
16
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C
32
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D
8
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Solution

The correct option is D 8
18×r5=128r5=128×8=1024r=4.
Thus, the series would be 18,12,2,8,32,128.
The third geometric mean would be 8.

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