Four girls $(G_{1}, G_{2}, G_{3}, G_{4})$ and three boys $(B_{1}, B_{2}, B_{3})$ are to sit for a dinner such that neither two boys nor two girls sit together. If they are seated in their numerical order, what is the position of $B_{2}$ and $G_{3}$ ?

5th and 6th

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4th and 5th

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3rd and 4th

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1st and 2nd

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Solution

The correct option is B
4th and 5th

Seating arrangement is as follows:

$\begin{matrix} 1^{s t} & 2^{n d} & 3^{r d} & 4^{t h} & 5^{t h} & 6^{t h} & 7^{t h} G_{1} & B_{1} & G_{2} & B_{2} & G_{3} & B_{3} & G_{4} \end{matrix}$

The number of boys is less than girls, so we should begin with a girl.

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Similar questions

Four girls $(G_{1}, G_{2}, G_{3}, G_{4})$ and three boys $(B_{1}, B_{2}, B_{3})$ are to sit for a dinner such that neither two boys nor two girls sit together. If they are seated in their numerical order, what is the position of $B_{2}$ and $G_{3}$ ?

Q. Directions:- Study the following information carefully to answer the question given below.

4 girls and 3 boys,

(G_{1}, G_{2}, G_{3} and G_{4}) a n d (B_{1}, B_{2} and B_{3})

are to sit for a dinner such that no two boys nor two girls should sit together.
If they are successively sitting, what is the position of

B_{2} a n d G_{3}

Q. If four boys are to be seated for a dinner such that no two girls and no two boys sit together.Find the number of ways in which they can be seated?

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girls sit in a straight line. Find the number of ways in which they can be seated if two girls are together and other

2

are also together but separate from the first two

5 girls and 5 boys are to be seated around a circular table such that no 2 girls will sit together. The number of ways in which they can be seated around the table is

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Four girls (G1,G2,G3,G4) and three boys (B1,B2,B3) are to sit for a dinner such that neither two boys nor two girls sit together. If they are seated in their numerical order, what is the position of B2 and G3?

The correct option is B 4th and 5th Seating arrangement is as follows: 1st2nd3rd4th5th6th7thG1B1G2B2G3B3G4 The number of boys is less than girls, so we should begin with a girl.

Four girls $(G_{1}, G_{2}, G_{3}, G_{4})$ and three boys $(B_{1}, B_{2}, B_{3})$ are to sit for a dinner such that neither two boys nor two girls sit together. If they are seated in their numerical order, what is the position of $B_{2}$ and $G_{3}$ ?

The correct option is B
4th and 5th

Seating arrangement is as follows:

$\begin{matrix} 1^{s t} & 2^{n d} & 3^{r d} & 4^{t h} & 5^{t h} & 6^{t h} & 7^{t h} G_{1} & B_{1} & G_{2} & B_{2} & G_{3} & B_{3} & G_{4} \end{matrix}$

The number of boys is less than girls, so we should begin with a girl.