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Question

Four grams of hydrocarbon (CxHy) on complete combustion gave 12 g of CO2. What is the empirical formula of the hydrocarbon?

A
CH3
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B
C4H9
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C
CH
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D
C3H8
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Solution

The correct option is D C3H8
CxHy+(x+y4)O2xCO2+y2H2O
1 mole of CxHy gives x moles of CO2
Given 412x+y moles of CxHy gives 1244 moles of CO2
4x12x+y=1244
or, 8x=3y
xy=38
Therefore, Empirical formula of the hydrocarbon is C3H8 .

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