Four identical bulbs each rated 100 watt, 220 volts are connected across a battery as shown. The total electric power consumed by the bulbs is :
A
75 watt
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B
400 watt
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C
300 watt
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D
400/3 watt
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Solution
The correct option is A75 watt From figure we see the combination of bulb in series and parallel,so replaced all the bulb with unknown resistance "R" Power(P)=v2R so,Resistance{R}=v2P=2202100=484Ω. on solving the equivalent resistance of the circuit we find Requivalent=645.33Ω. therefore total power across the circuit will be(P)=v2R=2202645.33=75watt