Four identical capacitors are connected in series with a 10V battery as shown in the figure. The point N is earthed, The potentials of points A and B are :
A
10V,0V
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B
7.5V,−2.5V
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C
5V,−5V
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D
7.5V,2.5V
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Solution
The correct option is B7.5V,−2.5V As the all capacitance are same and in series so potential across each =10/4=2.5V now, VA−VN=2.5+2.5+2.5=7.5 or VA−0=7.5⇒VA=7.5V and VN−VB=2.5 or 0−VB=2.5 or VB=−2.5V