Question

Four identical charges each of charge are placed at the corners of a square. Then at the centre of the square the resultant electric intensity E and the net electric potential V are

• A. $E\ne 0,V=0$
• B. $E=0$, $V=0$
• C. $E=0,V\ne 0$
• D. $E\ne 0,V\ne 0$

Answer 1

The correct option is C $E=0,V\ne 0$

$\to$ electic field by the diagonality opposits changes canal each other

$\therefore E=0$

voltage:

we know $V=\frac{KV}{e}$ ( E is vector V is a scalar )

$V=\frac{\sqrt{2}KV}{a}$

total $V=\frac{4\sqrt{2}KV}{a}$

$\therefore E=0,V\ne 0$