Four identical charges Q are fixed at the four corners of a square of side a. The electric field at a point P located symmetrically at a distance a/√2 from the center of the square is:
A
Q2√2πε0a2
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B
Q√2πε0a2
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C
2√2Qπε0a2
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D
√2Qπε0a2
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Solution
The correct option is BQ√2πε0a2
as shown in horizontal components of the forces cancel each other but vertical components are in same direction and of equal magnitude Ecosθ hence,