Four identical electrical lamps are labelled 1.5V,0.5A, which describes the condition necessary for them to operate at normal brightness. A12V battery of negligible internal resistance is connected to lamps as shown then
A
The value of R for normal brightness of each lamp is (3/4)Ω
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B
The value of R for normal brightness of each lamp is (21/4)Ω
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C
Power dissipated in R is 21 when all lamps are normally bright
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D
Total power dissipated in circuit when all lamps are normally bright is 24W
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Solution
The correct option is B The value of R for normal brightness of each lamp is (21/4)Ω Figure shown below is for normal brightness of each bulb
Given, Current through each bulb i0=0.5A
For 4 electric bulbs, current through mains supply ⇒i0=(0.5)4=2A
Also, voltage drop across each bulb V0=1.5V
Then, voltage drop across resistaance VR=E−V0=12−1.5=10.5V
Where E=12V is emf of battery
Hence for resistance R, we know that VR=iR ⇒10.5=i×R=2×R R=214Ω