Four identical plates of mass M and length L are placed on one another on the table so as to produce the maximum overhang as shown in the figure. The maximum total overhang will be:
A
3L4
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B
24L25
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C
25L24
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D
4L3
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Solution
The correct option is B25L24
If we take the displacement of the whole system to be x. So, when the four identical plates are placed one upon the other in such a manner that it will produce maximum overhang. Then each plates center of gravity must remain constant.
So, if the mass of the plates are M and length L.
So, Mx=M(L/2-x)
which on solving we will get the value of x=L/4.
Again for the n number blocks we will have
M(L/2 - xn) = M(n-1)xn
which on solving we will get L/2n.
So, for the 4 blocks we will get L/2,L/4,L/6,L/8 which will be 24L/25.