Four identical rods AB, CD, CF and DE are joined as shown in figure. The length, cross -sectional area and thermal conductivity of each rod are l, A and K respectively. The ends A, E and F are maintained at temperatures T1,T2 and T3 respectively. Assuming no loss of heat to the atmosphere, find the temperature at B.
Let the temperature at B be T
QAt=QBt+QCt
⇒KA(T−T1)l=KA(T−T2)l+12
+KA(T−T3)3l2
⇒(T−T1)l=(T−T2)l+12+(T−T3)3l2
⇒T−T1=23(2T−T2−T3)
⇒3T−3T1=4T−2(T2+T3)
⇒−7T=+3T1−2(T2+T3)
⇒T=−3T1+2(T2+T3)7