Four married couples are to be seated in a row having $8$ chairs. The number of ways so that spouses are seated next to each other is

72

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186

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384

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516

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Solution

The correct option is D $384$
Arrange four couple ( both together) in $4!$ ways
and arrange themselves in $2!$ ways each
Hence total number of arrangements $= 4! (2!)^{4} = 24 \cdot 16 = 384$

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Four married couples are to be seated in a row having 8 chairs. The number of ways so that spouses are seated next to each other is

The correct option is D 384Arrange four couple ( both together) in 4! waysand arrange themselves in 2! ways eachHence total number of arrangements =4!(2!)4=24⋅16=384

Four married couples are to be seated in a row having $8$ chairs. The number of ways so that spouses are seated next to each other is

The correct option is D $384$
Arrange four couple ( both together) in $4!$ ways
and arrange themselves in $2!$ ways each
Hence total number of arrangements $= 4! (2!)^{4} = 24 \cdot 16 = 384$