Four men lift a 250 kg box to a height of 1 m and hold it without raising or lowering it. How much work is done by the men in lifting the box? ( $g = 10 m s^{- 2}$ )

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Solution

Step 1: Given data
Mass of box, $m = 250 k g$
Height, $h = 1 m$
Acceleration due to gravity, $g = 10 m s^{- 2}$
Step 2: Formula used
$W = F \times h [w h e r e W = w o r k, F = F o r c e, h = h e i g h t]$
Step 3: Calculating work done by men in lifting the box
As we know that force, $F = m \times g [w h e r e m = m a s s, g = a c c e l e r a t i o n d u e t o g r a v i t y]$
Using the above formulas,
$W = F \times h W = m \times g \times h W = 250 \times 10 \times 1 W = 2500 J$
Therefore, the work done by the men in lifting the box is $2500 J$

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(g = 10 m s^{- 2})

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(g = 10 m s^{- 2})

Four men lift a $250 k g$ box to a height of $1 m$ and hold it without raising or lowering it.

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