Question

Four message signals are multiplexed using DM. Each sample is encoded with 16 bits and 4 bits are sued for synchronization at the end of each frame. Sampling time is 2 msec. The bit rate. (in kbps) is

• A. 40
• B. 32.5
• C. 34
• D. 32

Answer 1

The correct option is C 34

$R_b=(Nn+a)f_s$

$=\frac{(4\times 16+4)\times {10}^3}{2}$

1 frame = 4 sample; 1 frame has 4 extra bits = a

$R_b=34\times {10}^{3}bps=34kbps$