Four nuclei of an element undergo fusion to form a heavier nucleus, with release of energy. Which of the two-the parent nucleus or the daughter nucleus-would have higher binding energy per nucleon ?

Open in App

Solution

When lighter nuclei combine to form a heavier nucleus, binding energy per nucleon increases and energy is released. Thus, the daughter nucleus would have higher binding energy per nucleon than the parent nucleus.

Suggest Corrections

Similar questions

Q. Four nuclei of an element undergo fusion to form a heavier nucleus, with release of energy. Which of the two - the parent or the daughter nucleus - would have higher binding energy per nucleon?

Four nuclei of an element undergo fusion to form a heavier nucleus, with release of energy. whichof the 2 -the parent or the daughter nucleus would have higher binding energy per nucleon?

Q. Nuclei of two elements

P

and

Q

have binding energies

E_{P}

and

E_{Q} .

If four nuclei of element

Q

combine to give one

P

nucleus (as a daughter nucleus) releasing

e

units of energy along then

Q. For nuclei with A > 100,
(a) the binding energy of the nucleus decreases on an average as A increases
(b) the binding energy per nucleon decreases on an average as A increases
(c) if the nucleus breaks into two roughly equal parts, energy is released
(d) if two nuclei fuse to form a bigger nucleus, energy is released.

Q. The binding energy per nucleon for the parent nucleus is

E_{1}

and that for the daughter nuclei is

E_{2}

.Then

Join BYJU'S Learning Program