Four numbers are inserted between the numbers 4 and 39 such that an AP results. Which is the biggest of these four numbers?
32
Since 4 terms are inserted between 4 and 39 so there are 6 terms in the AP.
Therefore, the terms of the AP ar given by: 4, 4 + d, 4 + 2d, 4 + 3d, 4 + 4d, 4+5d
⇒39=4+5d,
⇒d=7,
So, as it is an increasing AP, therefore 4+4d would be the biggest.
⇒4+4d=4+4×7=4+28=32