Question

Four particles A,B,C and D are situated at the vertices of a square of side 'a' at t = 0. Each of the particles move with a constant speed 'v' such that A aims towards B, B aims towards C, C aims towards D and D aims towards A, then

• A. Particles will meat at center of square at $t=\frac{\sqrt{2}a}{v}$
• B. Particles will meat at center of square at $t=\frac{a}{v}$
• C. Distance travelled by any particle before meeting at center is $vt$
• D. Speed of approach of A and B is $\sqrt{2}v$

Answer 1

Answer: (B), (C)

The correct options are
B Particles will meat at center of square at $t=\frac{a}{v}$
C Distance travelled by any particle before meeting at center is $vt$


Speed of approach is $V_{app}=v$
By $V_{app}=\frac{\text{Seperation}}{\text{time}}$
$V=\frac{a}{t}\Rightarrow t=\frac{a}{v}$
By $\text{Speed}=\frac{\text{Distance}}{\text{Time}}=\text{Distance}=vt$