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Question

Four particles A,B,C and D are situated at the vertices of a square of side 'a' at t = 0. Each of the particles move with a constant speed 'v' such that A aims towards B, B aims towards C, C aims towards D and D aims towards A, then


A
Particles will meat at center of square at t=2av
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B
Particles will meat at center of square at t=av
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C
Distance travelled by any particle before meeting at center is vt
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D
Speed of approach of A and B is 2v
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Solution

The correct options are
B Particles will meat at center of square at t=av
C Distance travelled by any particle before meeting at center is vt

Speed of approach is Vapp=v
By Vapp=Seperationtime
V=att=av
By Speed=DistanceTime=Distance=vt

Physics

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