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Question

Four particles A,B,C and D with masses mA=m,mB=2m,mC=3m and mD=4m are at the corners of a square. They have accelerations of equal magnitude with directions as shown. The acceleration of the centre of mass of the particles in ms2 is

A
a5(^i^j)
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B
a(^i+^j)
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C
Zero
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D
a5(^i+^j)
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Solution

The correct option is A a5(^i^j)
For a system of discrete masses, acceleration of centre of mass (CM) is given by
aCM=mAaA+mBaB+mCaC+mDaDmA+mB+mC+mD


where, mA=m,mB=2m,mC=3m and mD=4m,
|aA|=|aB|=|aC|=|aD|=a (according to the question)
aCM=ma^i+2ma^j+3ma^i4ma^jm+2m+3m+4m
=2a^i2a^j10=a5.(^i^j) ms2

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