Four particles, each of mass 'm', are placed at the corners of a square of side 'a' shown in the figure. The position vector of the centre of mass is

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Solution

The correct option is B

The (x, y) co-ordinates of the masses at O, A, B and C respectively are
$(x_{1} = 0, y_{1} = 0), (x_{2} = a, y_{2} = 0), (x_{3} = a, y_{3} = a), (x_{4} = 0, y_{4} = a) .$
Therefore, the (x,y) co-ordinates of the centre of mass are
$x_{C M} = \frac{a}{2} a n d y_{C M} = \frac{a}{2}$ . The position vector of the centre of mass is
$\frac{a}{2} (i + j)$ , which is choice (b)

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Four particles, each of mass 'm', are placed at the corners of a square of side 'a' shown in the figure. The position vector of the centre of mass is

The correct option is B The (x, y) co-ordinates of the masses at O, A, B and C respectively are (x1=0,y1=0),(x2=a,y2=0),(x3=a,y3=a),(x4=0,y4=a). Therefore, the (x,y) co-ordinates of the centre of mass are xCM=a2andyCM=a2. The position vector of the centre of mass is a2(i+j), which is choice (b)