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Question

Four particles, each of mass 'm', are placed at the corners of 'a' square of side a in the x – y plane. If the origin of the co-ordinate system is taken at the point of intersection of the diagonals of the square, the co - ordinates of the centre of mass of the system are

A
(a, a)
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B
(–a, a)
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C
(a, –a)
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D
(0,0)
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Solution

The correct option is D (0,0) Given AB = BC = CD = AD =a. The (x, y) co-ordinates of the masses at A, B, C and D respectively are (x1=−a2y1=−a2),(x2=a2,y2=−a2) (x3=a2,y3=a2),(x4=−a2,y4=a2) It is easy to see that the co-ordinates of the centre of mass are (0, 0). Hence the correct choice is (d)

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