Four particles having masses m,2m,3m,4m are placed at four corners of a square of edge a.Find the gravitational force acting on a particle of mass m placed at the centre.

Open in App

Solution

Lets say, the force between the mass placed at the centre and the mass "m" at the corner A (say topleft) is F = Gm^2/(a/root[2])^2

So the other forces will be 2F, 3F and 4F towards B,C,D respectively (say B is top right) and so on.

So the resultant Force will be 2root(2)F in the downward direction (vertical)

which is 4root(2)Gm^2/a^2 (vertically downwards. {for this configuratoin of masses).

Suggest Corrections

Similar questions

Q. Four particles of masses

m, 2 m, 3 m

and

4 m

are placed at the corners of a square of side length

a

. The gravitational force on a particle on a particle of mass

m

placed at the centre of the square is

Four particles of masses m, 2m, 3m and 4m are kept in sequence at the corners of a square of side a. The magnitude of gravitational force acting on a particle of mass m placed at the centre of the square will be

Q. Four particles of masses

m, m, 2 m

and

2 m

are placed at the four corners of a square of side

a

as shown in the figure. The magnitude of the gravitational force acting on a particle of mass

m

placed at the centre of the square is

Join BYJU'S Learning Program