Four particles of mass 5, 3, 2 and 4 kg are at the points (1,6), (-1,5), (2,-3) and (-1,-4) respectively. Find the coordinate of their centre of mass.

(\frac{2}{7}, \frac{23}{4})

No worries! We‘ve got your back. Try BYJU‘S free classes today!

(\frac{1}{7}, \frac{23}{14})

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

(\frac{2}{7}, \frac{11}{4})

No worries! We‘ve got your back. Try BYJU‘S free classes today!

(\frac{1}{7}, \frac{23}{3})

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B $(\frac{1}{7}, \frac{23}{14})$
$x_{c o m} = \frac{5 \times 1 - 3 \times 1 + 2 \times 2 + 4 \times - 1}{5 + 3 + 2 + 4} = \frac{1}{7}$
$y_{c o m} = \frac{6 \times 5 + 3 \times 5 - 2 \times 3 + 4 \times (- 4)}{14}$
$= \frac{30 + 15 - 6 - 16}{14} = \frac{45 - 22}{14} = \frac{23}{14}$

Suggest Corrections

Similar questions

Q. Four particle of mass

5, 3, 2, 4 k g

are at the points

(1, 6), (- 1, 5), (2, - 3), (- 1, - 4)

. Find the coordinates of their center of mass.

The position vectors of three particles are (i + 2j + 3k), (5i - 2j + 2k) and (3i - 6j + 4k) and their masses are respectively 2 kg, 1 kg and 3 kg. The position vector of a fourth mass of 4 kg, so that the centre of mass of the system may be at the origin, is

Q. Four particles of masses

1 kg, 2 kg, 3 kg

and

4 kg

are placed at the four vertices

A,B,C

and

D

of a square of side

1 m

as shown in figure. Find the position of centre of mass of the particles.

Four particles of masses 1 kg, 2 kg, 3 kg and 4 kg are placed at the corners of a square of side 2 m in the x-y plane as shown in the figure. If the origin of the coordinate system is taken at the mass of 1 kg, the (x, y) co-ordinates of the centre of mass are