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Center of Mass as an Average Point

Four particle...

Question

Four particles of masses $m_{1}, m_{2}, m_{3}$ and $m_{4}$ are placed at the vertices A,B,C and D of a square as shown respectively. The COM of the system will lie on diagonal AC if:

A

m_{1} = m_{4}

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B

m_{2} = m_{4}

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C

m_{1} = m_{2}

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D

m_{3} = m_{4}

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Solution

The correct option is B $m_{2} = m_{4}$
COM will lie on diagonal AC, if masses are distributed symmetrically around AC i.e. COM will be equidistant from B and D if $m_{2} = m_{4}$ .

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