Question

Four persons A, B, C and D at the corners of an square of side $X$ move at a constant speed $V$. Each person maintains a direction towards the person at the next corner. The time, the persons take to meet each other is

• A. $\frac{2X}{3V}$
• B. $\frac{2X}{V}$
• C. $\frac{X}{V}$
• D. $\frac{3X}{4V}$

Answer 1

Answer: (C)

$\frac{X}{V}$

Relative velocity of particle 2 along direction of particle 1 is $V_{2/1}=V$,

The relative distance of particle 1 w.r.t. 2 is $X$.

Time taken by particle 2 to reach particle 1 is $t=\frac{X}{V}$