Question

Four persons draw each a card from an ordinary pack: find the chance that a card is of each suit

Answer 1

All four cards are of different suits

Probability of the second person drawing a card of different suit $=\frac{39}{51}$

Probability of the third person drawing a card of different suit $=\frac{26}{50}$

Probability of the fourth person drawing a card of different suit $=\frac{13}{49}$

Therefore, probability that all four cards are of different suits $=\frac{39}{51}\times \frac{26}{50}\times \frac{13}{49}=\frac{2197}{20825}$