Four pipes each of 5 cm in diameter are to be replaced by a single pipe discharging the same quantity of water. If the speed of water remains same in both the cases, then the diameter (in cm) of the single pipe is:
5
Four pipes each of 5cm in diameter
⇒ radius r =2.5 cm
Let the height be h.
Volume of small pipe =πr2h
(since we are considering the height (length) of the pipe as constant or same)
Let the height be h
Volume of new pipe = Sum of volumes of all small pipes
πR2h=4×π×(2.5)2×h
R2=4×(2.5)2
R=2×(2.5)=5cm