Question

Four plates of same area of cross-section are joined as shown in figure. The distance between each plate is d. The equivalent capacity between A and B will be

• A. $\frac{2{ϵ}_{0}A}{d}$
• B. $\frac{{ϵ}_{0}A}{d}$
• C. $\frac{3{ϵ}_{0}A}{d}$
• D. $\frac{3{ϵ}_{0}A}{2d}$

Answer 1

Answer: (C)

$\frac{3{ϵ}_{0}A}{d}$

The given arrangement is equivalent to the parallel combination of three identical capacitors.
Hence, equivalent capacitance $=3C=\frac{3{ϵ}_{0}A}{d}$