Four point charges, each equal to $q = 4 μ C$ , are held at the corners of a square ABCD of side a = 10cm. Find the magnitude and sign of a charge Q placed at the centers of the square so that the system of charges is in equilibrium.

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Solution

Since all the corners of the square have the same magnitude of $4 μ C$ to maintain the equilibrium of the system.

$F_{A} + F_{B} + F_{C} + F_{D} = 0$

For that Q can be any magnitude and sign as the system is symmetrically balanced.

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Four point charges, each equal to q=4μC, are held at the corners of a square ABCD of side a = 10cm. Find the magnitude and sign of a charge Q placed at the centers of the square so that the system of charges is in equilibrium.

Since all the corners of the square have the same magnitude of 4μC to maintain the equilibrium of the system.FA+FB+FC+FD=0For that Q can be any magnitude and sign as the system is symmetrically balanced.

Four point charges, each equal to $q = 4 μ C$ , are held at the corners of a square ABCD of side a = 10cm. Find the magnitude and sign of a charge Q placed at the centers of the square so that the system of charges is in equilibrium.

Since all the corners of the square have the same magnitude of $4 μ C$ to maintain the equilibrium of the system.

$F_{A} + F_{B} + F_{C} + F_{D} = 0$

For that Q can be any magnitude and sign as the system is symmetrically balanced.