Byju's Answer
Standard XII
Physics
Capacitance of a Random Conductor
Four point ch...
Question
Four point charges of 1 μC, 2 μC, 3 μC, and 4 μC, are placed along x axis at x = 1 m, x = 2 m, x = 3 m and x = 4 m respectively. The electric field intensity at origin due to first three charges is
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Q.
Three point charges
q
1
=
1
μ
C
,
q
2
=
−
2
μ
C
and
q
3
=
3
μ
C
are placed at
(
1
m
,
0
,
0
)
and
(
0
,
2
m
,
0
)
and
(
0
,
0
,
3
m
)
respectively. The electric potential at origin is
Q.
Four charges of
6
μ
C
,
2
μ
C
,
−
12
μ
C
and
4
μ
C
are placed at the corners of a square of side
1
m
. The square is in xy-plane and its center at its origin. Electric potential due to these charges is zero everywhere on the line
Q.
Two point charges
q
1
=
−
1
μ
C
and
q
2
=
+
1
μ
C
are located on the
x
−
axis, at
x
=
0
m
and at
x
=
1
m
respectively. The work that must be done by an external force to bring a third point charge
q
3
=
+
1
μ
C
from infinity to
x
=
2
m
is
Q.
Four point charges
+
8
μ
C
,
−
1
μ
C
,
+
8
μ
C
and
−
1
μ
C
are fixed at the points
−
√
27
/
2
m
,
−
√
3
/
2
m
,
+
√
3
/
2
m
and
√
27
/
2
m
respectively, on the y-axis. A particle of mass
6
×
10
−
4
k
g
and charge +0.1
μ
C
moves along the x-direction. Its speed at x = +
∞
is
V
o
. Find the least value of
V
o
for which the particle will cross the origin. Find also the kinetic energy of the particle at the origin. Assume that space is gravity free. Given
(
1
/
4
π
ε
0
)
=
9
×
10
9
N
m
2
C
−
2
.
Q.
Two point charges
q
1
(
√
10
μ
C
)
and
q
2
(
−
25
μ
C
)
are placed on the x-axis at
x
=
1
m
and
x
=
4
m
respectively.The electric field in
(
V/m
)
at a point
y
=
3
m
on
y
−
axis is
[
Take
1
4
π
ε
0
=
9
×
10
9
Nm
2
C
−
2
]
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Standard XII Physics
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