Four point masses are placed at four corners of a square as shown. When positions of m and 2m are interchanged
E=Gmr2
E′net=2√2E=2√2Gmr2
E′net=√(9E)2+E2
=√10E
=√10Gmr2
E′net>Enet
Potential in both cases is
Vnet=−Gr(m+2m+3m+4m)
=−10Gmr