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Question

Four point size bodies each of mass m are fixed at four corners of a light square frame of side length L. The radius of gyration of these four bodies about an axis perpendicular to the plane of frame passing through its centre is:

A
2L
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B
2L
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C
L2
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D
L2
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Solution

The correct option is C L2
I=4m(L2)2
=2mL2
So we have radius of gyration equivalence equation as,
4mk2=2mL2
k=L2

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