Question

Four quantum numbers of unpaired electron of chlorine are :

• A. $n=3,l=2,m=0,s=+1/2$
• B. $n=3,l=1,m=0,s=+1/2$
• C. $n=3,l=1,m=+1,s=0$
• D. $n=3,l=0,m=-1,s=+1/2$

Answer 1

The correct option is B $n=3,l=1,m=0,s=+1/2$

The electronic configuration of chlorine is $1s^{2}2s^{2}2p^{6}3s^{2}3p^5$.
The unpaired electron of Cl belongs to 3p orbital.
For a p orbital, $l=1$ and $m=-1,0or+1$.
Four quantum numbers of unpaired electron of chlorine are $n=3,l=1,m=0,s=+1/2$.