Question

Four resistances $10\Omega ,5\Omega ,7\Omega$ and $3\Omega$ are connected so that they form the sides of a rectangle $AB,BC,CD$ and $DA$ respectively. Another resistance of $10\Omega$ is connected across the diagonal $AC$. The equivalent resistance between $A$ and $B$ is

• A. $2\Omega$
• B. $5\Omega$
• C. $7\Omega$
• D. $10\Omega$

Answer 1

Answer: (B)

$5\Omega$

$R_{AB}=\frac{10\times 10}{10\times 2}=5\Omega$