Question

Four resistances $10\Omega ,5\Omega ,7\Omega$ and $3\Omega$ are connected so that they form the sides of a rectangle AB, BC, CD and DA respectively. Another resistance of $10\Omega$ is connected across the diagonal AC. The equivalent resistance between A and B is

• A. $2\Omega$
• B. $5\Omega$
• C. $7\Omega$
• D. $10\Omega$

Answer 1

The correct option is B $5\Omega$


So
$R_{eq}=\frac{10\times 10}{10+10}=5\Omega$