Question

Four resistances are connected in a circuit as shown in the following diagram. The value of the current in ampere in 4ohm and 6ohm resistance are :

• A. 2 and 4
• B. 1 and 2
• C. 1 and 1
• D. 2 and 2

Answer 1

The correct option is D 2 and 2

Here, $R_1=4||4=4/2=2\Omega$ and $R_2=6||6=6/2=3\Omega$
Current in the circuit is $I=\frac{V}{R_1+R_2}=\frac{20}{2+3}=4A$
As $\left(4||4\right)$ and $\left(6||6\right)$ are in series so same current I will flow through these branches.
In parallel branches two resistances are same so current through each resistance will be $I/2=2A$