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Introduction and Degree of Hydrolysis

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Question

Four solutions of $N H_{4} C l$ are taken with concentrations $1 M, 0.1 M, 0.01 M a n d 0.001 M$ . Their degree of hydrolysis are $h_{1}, h_{2}, h_{3}$ and $h_{4}$ . What is the decreasing order of degree of hydrolysis ?

h_{1} > h_{2} > h_{3} > h_{4}

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h_{1} = h_{2} = h_{3} = h_{4}

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h_{4} > h_{3} > h_{2} > h_{1}

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None of these

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Solution

The correct option is C $h_{4} > h_{3} > h_{2} > h_{1}$
$N H_{4} C l \to$ Salt of strong acid, $H C l$ and weak base $N H_{4} O H$
$\to$ Degree of hydrolysis, $h = \sqrt{\frac{k_{h}}{C}} = \sqrt{\frac{k_{w}}{k_{b} C}}$
$\to$ Higher the concentration, lower will be the degree of hydrolysis.
Hence, $h_{1} < h_{2} < h_{3} < h_{4}$

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Four solutions of NH4Cl are taken with concentrations 1 M, 0.1 M, 0.01 M and 0.001 M. Their degree of hydrolysis are h1,h2,h3 and h4. What is the decreasing order of degree of hydrolysis ?

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Four solutions of $N H_{4} C l$ are taken with concentrations $1 M, 0.1 M, 0.01 M a n d 0.001 M$ . Their degree of hydrolysis are $h_{1}, h_{2}, h_{3}$ and $h_{4}$ . What is the decreasing order of degree of hydrolysis ?