    Question

# Four uniform rods of mass m kg each form a rectangle as shown in figure. The rods have negligible area of cross-section. Find the position of center of mass of the rectangle made up of the four uniform rods. A
(2,2) m
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B
(2,0) m
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C
(2,1) m
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D
(4,2) m
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Solution

## The correct option is C (2,1) m Given, mass of each rod =m kg Co-ordinate of COM of rod I, (x1,y1)=(2,0) m Co-ordinate of COM of rod II, (x2,y2)=(0,1) m Co-ordinate of COM of rod III, (x3,y3)=(2,2) m Co-ordinate of COM of rod IV, (x4,y4)=(4,1) m Therefore, x− co-ordinate of COM of rectangle xCOM=m1x1+m2x2+m3x3+m4x4m1+m2+m3+m4 [m1=m2=m3=m4=m] =m×2+m×0+m×2+m×4m+m+m+m =8m4m=2 m and y− co-ordinate of COM of rectangle yCOM=m1y1+m2y2+m3y3+m4y4m1+m2+m3+m4 =m×0+m×1+m×2+m×1m+m+m+m =4m4m=1 m The position of center of mass of the rectangle is (xCOM,yCOM)=(2,1) m  Suggest Corrections  0      Similar questions  Explore more