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Permutation

Four visitors...

Question

Four visitors A,B,C &D arrive at a town which has 5 hotels. In how many ways can they disperse themselves among 5 hotels, If 4 hotels are used to accommodate them.

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Solution

$∴ P e r m u t a t i o n = 5 \times 4 \times 3 \times 2 = 120 w a y s$

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