CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Four wires each of length 2.0 m are bent into four loops P, Q, R and S and then suspended into uniform magnetic field which is from left to right. Same current is passed in each loop. Which of the following statement is correct ?

A
Couple on loop P will be the highest
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
Couple on loop Q will be the highest
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
Couple on loop R will be the highest
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
Couple on loop S will be the highest
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The correct option is D Couple on loop S will be the highest
for a given perimeter , a circle has the largest area So,
τ=M×B
τ=nIAB
ταA
Now, greater area leads to more torque
So, loop S will have highest torque (couple).

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Second Law of Motion
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon