Question

Four years ago age of a person was $4$ times that of his son. Six years later the age of the person will be $10$ years less than thrice the age of his son. Find the present age of the person.

Answer 1

Let the present ages of the person and his son be $x$ years and $y$ years respectively.
Given, $x-4=4(y-4)$
$\Rightarrow x-4=4y-16$

$\Rightarrow x-4y=-12$ ....(1)
And also given, $x+6=3(y+6)-10$
$\Rightarrow x+6=3y+8$

$\Rightarrow x-3y=2$ ....(2)
By solving the equations (1) and (2), we get

$x=44$ and $y=14$