Question

Four years ago the father was 10 times as old as his son. Four years from now the father‘s age would be 4 times that of his son. Find the sum of present ages of father and son?

• A. 52 years
• B. 63 years
• C. 45 years
• D. 56 years
• E. None of the above

Answer 1

The correct option is A 52 years

Let the present ages of father and son be = x and y
4 years ago x - 4 = 10 (y - 4) --- (1)
4 years from now x +4 = 4 (y + 4) -- (2)
Solving (1) and (2), we get x = 44 and y = 8
Sum of their ages = 44 + 8 = 52 years