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B
130
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C
124
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D
118
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Solution
The correct option is C124 S=11.4.7+14.7.10+⋯ n temrs Tr=1(3r−2)(3r+1)(3r+4) Tr=16[1(3r−2)(3r+1)−1(3r+1)(3r+4)] T1=16[11.4−14.7] T2=16[14.7−17.10] Tn=16[1(3n−2)(3n+1)−1(3n+1)(3n+4)] Sn=T1+T2+⋯+Tn Sn=16[11.4−1(3n+1)(3n+4)] If n→∞,S∞=124