11−sinA+11+sinA=2sec2A
11−sinA+11+sinA =(1+sinA+1−sinA)(1−sinA)(1+sinA) =2(1−sin2A) =2cos2A [∵, sin²A+cos²A=1] =2sec²A (Proved)
Prove the following trigonometric identities:
11+sin A+11−sin A=2 sec2 A
( √1 + sin A / √ 1- sin A ) + ( √1 - sin A / √ 1 + sin A ) = 2 sec A