1-2-1-22-1-23-1-24-1-25-1-26-1-27-

The correct option is B 1 1/2^7 In general, the sum of the powers 1/2 , 1/2^2 ,1/2^3 and so on is equal to the last power subtracted from 1 ...

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Sum of Powers

1/2+1/22+1/23...

Question

$\frac{1}{2} + \frac{1}{2^{2}} + \frac{1}{2^{3}} + \frac{1}{2^{4}} + \frac{1}{2^{5}} + \frac{1}{2^{6}} + \frac{1}{2^{7}}$ =___

$1 - \frac{1}{2^{6}}$

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$1 - \frac{1}{2^{7}}$

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$1 - \frac{1}{2^{3}}$

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$1 - \frac{1}{2^{4}}$

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Solution

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Similar questions

\sqrt{1 + 23 \sqrt{1 + 24 \sqrt{1 + 25 \sqrt{26 \times 28 + 1}}}}

\frac{{(\frac{1}{2})}^{5} - {(\frac{1}{2})}^{6}}{{(\frac{1}{2})}^{3} - {(\frac{1}{2})}^{5}}

{\frac{1}{1 \times 2}}^{25} C_{0} + {\frac{1}{2 \times 3}}^{23} C_{1} + {\frac{1}{3 \times 4}}^{25} C_{2} + . . . . . . + {\frac{1}{26 \times 27}}^{25} C_{25}

\frac{1}{2} (\frac{1}{2})^{2} + \frac{1}{4} (\frac{1}{2})^{4} + \frac{1}{6} (\frac{1}{2})^{6} + \dots \dots =

{(\frac{1}{2})}^{4} \times {(\frac{1}{2})}^{5} \times {(\frac{1}{2})}^{6}

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