Question

$\frac{1}{(3+2\sqrt{2})}=?$

(a)$\frac{3-2\sqrt{2}}{17}$

(b)$\frac{(3-2\sqrt{2})}{13}$

(c)$(3-2\sqrt{2})$

(d)None of these

Answer 1

$\frac{1}{(3+2\sqrt{2})}=\frac{1(3-2\sqrt{2})}{(3+2\sqrt{2})(3-2\sqrt{2})}=\frac{3-2\sqrt{2}}{3^2-(2\sqrt{2}{)}^2}=\frac{3-2\sqrt{2}}{9-8}=3-2\sqrt{2}$

Hence, the correct answer is option (c)