Question

$\frac{1}{3}$ and $\frac{1}{5}$ are first 2 terms of H.P. the 15th term of H.P is

• A.
• B.
• C.
• D.

Answer 1

The correct option is A

$\frac{1}{3}$, $\frac{1}{5}$, --------- form H.P.

3, 5, ------------ form A.P.

Common difference D = 2

So, nth term of H.P. = $\frac{1}{3+(n-1)2}$

15th term = $\frac{1}{3+14.2}$ = $\frac{1}{31}$