1-i-1-i2 - 1-i-1-i2 is equal to

(1+i)^2=1+i^2+2i=2i (1 i)^2=1+i^2 2i= 2i (1+i1 i)^2 + (1 i1+i)^2=2i 2i+ 2i2i= 1 1= 2 ...

You visited us 3 times! Enjoying our articles? Unlock Full Access!

Properties of Iota

1+i/1-i2 + 1-...

Question

$(\frac{1 + i}{1 - i})^{2} + \frac{1 - i}{1 + i})^{2})$ is equal to

Open in App

Solution

Suggest Corrections

Similar questions

{(\frac{1 + i}{1 - i})}^{2} + {(\frac{1 - i}{1 + i})}^{2}

${(\frac{1 + i}{1 - i})}^{2} + {(\frac{1 - i}{1 + i})}^{2}$ is equal to

{(\frac{1 + i}{1 - i})}^{2} + {(\frac{1 - i}{1 + i})}^{2}

{(\frac{1 + i}{1 - i})}^{2} + {(\frac{1 - i}{1 + i})}^{2}

1 + (1 + i) + (1 + i)^{2} + (1 + i)^{3} =

Join BYJU'S Learning Program