1+sin600∘−cos600∘1+sin600∘+cos600∘ = ?
-√3
Solution: Sin 600∘ = sin(360∘+240∘) = sin240∘
= sin (180∘+60∘) = -sin 60∘ = −√32
Cos600∘ = cos(360∘+240∘) = cos 240∘
= cos(180∘+60∘) = -cos 60∘ = −12
⇒ Expression = 1+(−√32)−(−12)1+(−√32)+(−12)
= 1−√32+121−√32−12 = 2−√3+122−√3−12 = 3−√31−√3
After rationalizing
= 3−√31−√3 × 1+√31+√3
= 3+3√3−√3−31−3 = 2√3−2 = -√3